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(8x+9)=(2x+79)
We move all terms to the left:
(8x+9)-((2x+79))=0
We get rid of parentheses
8x-((2x+79))+9=0
We calculate terms in parentheses: -((2x+79)), so:We get rid of parentheses
(2x+79)
We get rid of parentheses
2x+79
Back to the equation:
-(2x+79)
8x-2x-79+9=0
We add all the numbers together, and all the variables
6x-70=0
We move all terms containing x to the left, all other terms to the right
6x=70
x=70/6
x=11+2/3
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