(8x+3)+(4x+2)=41

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Solution for (8x+3)+(4x+2)=41 equation:


Simplifying
(8x + 3) + (4x + 2) = 41

Reorder the terms:
(3 + 8x) + (4x + 2) = 41

Remove parenthesis around (3 + 8x)
3 + 8x + (4x + 2) = 41

Reorder the terms:
3 + 8x + (2 + 4x) = 41

Remove parenthesis around (2 + 4x)
3 + 8x + 2 + 4x = 41

Reorder the terms:
3 + 2 + 8x + 4x = 41

Combine like terms: 3 + 2 = 5
5 + 8x + 4x = 41

Combine like terms: 8x + 4x = 12x
5 + 12x = 41

Solving
5 + 12x = 41

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 12x = 41 + -5

Combine like terms: 5 + -5 = 0
0 + 12x = 41 + -5
12x = 41 + -5

Combine like terms: 41 + -5 = 36
12x = 36

Divide each side by '12'.
x = 3

Simplifying
x = 3

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