(8x+2)(1-3x)+(6x-1)(4x-10)=-50

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Solution for (8x+2)(1-3x)+(6x-1)(4x-10)=-50 equation:



(8x+2)(1-3x)+(6x-1)(4x-10)=-50
We move all terms to the left:
(8x+2)(1-3x)+(6x-1)(4x-10)-(-50)=0
We add all the numbers together, and all the variables
(8x+2)(-3x+1)+(6x-1)(4x-10)-(-50)=0
We add all the numbers together, and all the variables
(8x+2)(-3x+1)+(6x-1)(4x-10)+50=0
We multiply parentheses ..
(-24x^2+8x-6x+2)+(6x-1)(4x-10)+50=0
We get rid of parentheses
-24x^2+8x-6x+(6x-1)(4x-10)+2+50=0
We multiply parentheses ..
-24x^2+(+24x^2-60x-4x+10)+8x-6x+2+50=0
We add all the numbers together, and all the variables
-24x^2+(+24x^2-60x-4x+10)+2x+52=0
We get rid of parentheses
-24x^2+24x^2-60x-4x+2x+10+52=0
We add all the numbers together, and all the variables
-62x+62=0
We move all terms containing x to the left, all other terms to the right
-62x=-62
x=-62/-62
x=1

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