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(8x+120)7x=180
We move all terms to the left:
(8x+120)7x-(180)=0
We multiply parentheses
56x^2+840x-180=0
a = 56; b = 840; c = -180;
Δ = b2-4ac
Δ = 8402-4·56·(-180)
Δ = 745920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{745920}=\sqrt{576*1295}=\sqrt{576}*\sqrt{1295}=24\sqrt{1295}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(840)-24\sqrt{1295}}{2*56}=\frac{-840-24\sqrt{1295}}{112} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(840)+24\sqrt{1295}}{2*56}=\frac{-840+24\sqrt{1295}}{112} $
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