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(8x+10)(6x+2)=180
We move all terms to the left:
(8x+10)(6x+2)-(180)=0
We multiply parentheses ..
(+48x^2+16x+60x+20)-180=0
We get rid of parentheses
48x^2+16x+60x+20-180=0
We add all the numbers together, and all the variables
48x^2+76x-160=0
a = 48; b = 76; c = -160;
Δ = b2-4ac
Δ = 762-4·48·(-160)
Δ = 36496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{36496}=\sqrt{16*2281}=\sqrt{16}*\sqrt{2281}=4\sqrt{2281}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-4\sqrt{2281}}{2*48}=\frac{-76-4\sqrt{2281}}{96} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+4\sqrt{2281}}{2*48}=\frac{-76+4\sqrt{2281}}{96} $
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