(8x+1)=(2x+13)

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Solution for (8x+1)=(2x+13) equation: 



(8x+1)=(2x+13)

We move all terms to the left:

(8x+1)-((2x+13))=0

We get rid of parentheses

8x-((2x+13))+1=0



We calculate terms in parentheses: -((2x+13)), so:

(2x+13)

We get rid of parentheses

2x+13

Back to the equation:

-(2x+13)



We get rid of parentheses

8x-2x-13+1=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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