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(8x+1)/(5x-4)=0
Domain of the equation: (5x-4)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x!=4
x!=4/5
x!=4/5
x∈R
(8x+1)=0
We get rid of parentheses
8x+1=0
We move all terms containing x to the left, all other terms to the right
8x=-1
x=-1/8
x=-1/8
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