(8x+1)(2x-7)=16X(x+3)

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Solution for (8x+1)(2x-7)=16X(x+3) equation: 



(8x+1)(2x-7)=16x(x+3)

We move all terms to the left:

(8x+1)(2x-7)-(16x(x+3))=0

We multiply parentheses ..

(+16x^2-56x+2x-7)-(16x(x+3))=0



We calculate terms in parentheses: -(16x(x+3)), so:

16x(x+3)

We multiply parentheses

16x^2+48x

Back to the equation:

-(16x^2+48x)



We get rid of parentheses

16x^2-16x^2-56x+2x-48x-7=0

We add all the numbers together, and all the variables

-102x-7=0

We move all terms containing x to the left, all other terms to the right

-102x=7

x=7/-102

x=-7/102

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