(8k-40)/(20-4k)

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Solution for (8k-40)/(20-4k) equation: 


D( k )

20-(4*k) = 0

20-(4*k) = 0

20-(4*k) = 0

20-4*k = 0

20-4*k = 0 // - 20

-4*k = -20 // : -4

k = -20/(-4)

k = 5

k in (-oo:5) U (5:+oo)

(8*k-40)/(20-(4*k)) = 0

(8*k-40)/(20-4*k) = 0

8*k-40 = 0 // + 40

8*k = 40 // : 8

k = 40/8

k = 5

k in { 5} 

k belongs to the empty set

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