(8h-5)(h-2)=0

Solution for (8h-5)(h-2)=0 equation:

(8h-5)(h-2)=0

We multiply parentheses ..

(+8h^2-16h-5h+10)=0

We get rid of parentheses

8h^2-16h-5h+10=0

We add all the numbers together, and all the variables

8h^2-21h+10=0

a = 8; b = -21; c = +10;
Δ = b2-4ac
Δ = -212-4·8·10
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-11}{2*8}=\frac{10}{16}
=5/8
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+11}{2*8}=\frac{32}{16}
=2
$