(8h+3)(5h+9)=0

Solution for (8h+3)(5h+9)=0 equation:

(8h+3)(5h+9)=0

We multiply parentheses ..

(+40h^2+72h+15h+27)=0

We get rid of parentheses

40h^2+72h+15h+27=0

We add all the numbers together, and all the variables

40h^2+87h+27=0

a = 40; b = 87; c = +27;
Δ = b2-4ac
Δ = 872-4·40·27
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(87)-57}{2*40}=\frac{-144}{80}
=-1+4/5
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(87)+57}{2*40}=\frac{-30}{80}
=-3/8
$