(80+2x)0,8=(40+x)0,2

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Solution for (80+2x)0,8=(40+x)0,2 equation: 



(80+2x)0.8=(40+x)0.2

We move all terms to the left:

(80+2x)0.8-((40+x)0.2)=0

We add all the numbers together, and all the variables

(2x+80)0.8-((x+40)0.2)=0

We multiply parentheses

1.6x-((x+40)0.2)+64=0



We calculate terms in parentheses: -((x+40)0.2), so:

(x+40)0.2

We multiply parentheses

0.2x+8

Back to the equation:

-(0.2x+8)



We get rid of parentheses

1.6x-0.2x-8+64=0

We add all the numbers together, and all the variables

1.4x+56=0

We move all terms containing x to the left, all other terms to the right

1.4x=-56

x=-56/1.4

x=-40

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