(8/x)+22=(2/3x)

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Solution for (8/x)+22=(2/3x) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

8/x+22 = (2/3)*x // - (2/3)*x

8/x-((2/3)*x)+22 = 0

(-2/3)*x+8/x+22 = 0

8*x^-1-2/3*x^1+22*x^0 = 0

(22*x^1-2/3*x^2+8*x^0)/(x^1) = 0 // * x^2

x^1*(22*x^1-2/3*x^2+8*x^0) = 0

x^1

(-2/3)*x^2+22*x+8 = 0

(-2/3)*x^2+22*x+8 = 0

DELTA = 22^2-(4*8*(-2/3))

DELTA = 1516/3

DELTA > 0

x = ((1516/3)^(1/2)-22)/(2*(-2/3)) or x = (-(1516/3)^(1/2)-22)/(2*(-2/3))

x = -3/4*((1516/3)^(1/2)-22) or x = 3/4*((1516/3)^(1/2)+22)

x in { -3/4*((1516/3)^(1/2)-22), 3/4*((1516/3)^(1/2)+22)}

x in { -3/4*((1516/3)^(1/2)-22), 3/4*((1516/3)^(1/2)+22) }

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