(8/r+2)+(8/r-2)=3

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Solution for (8/r+2)+(8/r-2)=3 equation: 



(8/r+2)+(8/r-2)=3

We move all terms to the left:

(8/r+2)+(8/r-2)-(3)=0



Domain of the equation: r+2)!=0

r∈R





Domain of the equation: r-2)!=0

r∈R



We get rid of parentheses

8/r+8/r+2-2-3=0

We multiply all the terms by the denominator


2*r-2*r-3*r+8+8=0

We add all the numbers together, and all the variables

-3r+16=0

We move all terms containing r to the left, all other terms to the right

-3r=-16

r=-16/-3

r=5+1/3

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