(8/9)x=2

Solution for (8/9)x=2 equation:

(8/9)x=2

We move all terms to the left:

(8/9)x-(2)=0


Domain of the equation: 9)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+8/9)x-2=0

We multiply parentheses

8x^2-2=0

a = 8; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·8·(-2)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*8}=\frac{-8}{16}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*8}=\frac{8}{16}
=1/2
$