(8/7)+(7m/3)=(80/21)

Solution for (8/7)+(7m/3)=(80/21) equation:

(8/7)+(7m/3)=(80/21)

We move all terms to the left:

(8/7)+(7m/3)-((80/21))=0

We add all the numbers together, and all the variables

(+7m/3)+(+8/7)-((+80/21))=0

We get rid of parentheses

7m/3+8/7-((+80/21))=0

We calculate fractions


2058m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

2058m^2/()+2=0

We multiply all the terms by the denominator


2058m^2+2*()=0

We add all the numbers together, and all the variables

2058m^2=0

a = 2058; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2058·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{4116}=0$