(8/11)m=96

Solution for (8/11)m=96 equation:

(8/11)m=96

We move all terms to the left:

(8/11)m-(96)=0


Domain of the equation: 11)m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+8/11)m-96=0

We multiply parentheses

8m^2-96=0

a = 8; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·8·(-96)
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{3}}{2*8}=\frac{0-32\sqrt{3}}{16}
=-\frac{32\sqrt{3}}{16}
=-2\sqrt{3}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{3}}{2*8}=\frac{0+32\sqrt{3}}{16}
=\frac{32\sqrt{3}}{16}
=2\sqrt{3}
$