(8/(x-5))-(8/(x-8))=12

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Solution for (8/(x-5))-(8/(x-8))=12 equation:


D( x )

x-5 = 0

x-8 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x-8 = 0

x-8 = 0

x-8 = 0 // + 8

x = 8

x in (-oo:5) U (5:8) U (8:+oo)

8/(x-5)-(8/(x-8)) = 12 // - 12

8/(x-5)-(8/(x-8))-12 = 0

8/(x-5)-8*(x-8)^-1-12 = 0

8/(x-5)-8/(x-8)-12 = 0

(8*(x-8))/((x-5)*(x-8))+(-8*(x-5))/((x-5)*(x-8))+(-12*(x-5)*(x-8))/((x-5)*(x-8)) = 0

8*(x-8)-8*(x-5)-12*(x-5)*(x-8) = 0

156*x-12*x^2-480-24 = 0

156*x-12*x^2-504 = 0

156*x-12*x^2-504 = 0

12*(13*x-x^2-42) = 0

13*x-x^2-42 = 0

DELTA = 13^2-(-42*(-1)*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)-13)/(-1*2) or x = (-1^(1/2)-13)/(-1*2)

x = 6 or x = 7

12*(x-6)*(x-7) = 0

(12*(x-6)*(x-7))/((x-5)*(x-8)) = 0

(12*(x-6)*(x-7))/((x-5)*(x-8)) = 0 // * (x-5)*(x-8)

12*(x-6)*(x-7) = 0

( 12 )

12 = 0

x belongs to the empty set

( x-6 )

x-6 = 0 // + 6

x = 6

( x-7 )

x-7 = 0 // + 7

x = 7

x in { 6, 7 }

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