(8-v)(2v-7)=0

Solution for (8-v)(2v-7)=0 equation:

(8-v)(2v-7)=0

We add all the numbers together, and all the variables

(-1v+8)(2v-7)=0

We multiply parentheses ..

(-2v^2+7v+16v-56)=0

We get rid of parentheses

-2v^2+7v+16v-56=0

We add all the numbers together, and all the variables

-2v^2+23v-56=0

a = -2; b = 23; c = -56;
Δ = b2-4ac
Δ = 232-4·(-2)·(-56)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-9}{2*-2}=\frac{-32}{-4}
=+8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+9}{2*-2}=\frac{-14}{-4}
=3+1/2
$