(8-2i)(1-i)=

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Solution for (8-2i)(1-i)= equation:


Simplifying
(8 + -2i)(1 + -1i) = 0

Multiply (8 + -2i) * (1 + -1i)
(8(1 + -1i) + -2i * (1 + -1i)) = 0
((1 * 8 + -1i * 8) + -2i * (1 + -1i)) = 0
((8 + -8i) + -2i * (1 + -1i)) = 0
(8 + -8i + (1 * -2i + -1i * -2i)) = 0
(8 + -8i + (-2i + 2i2)) = 0

Combine like terms: -8i + -2i = -10i
(8 + -10i + 2i2) = 0

Solving
8 + -10i + 2i2 = 0

Solving for variable 'i'.

Factor out the Greatest Common Factor (GCF), '2'.
2(4 + -5i + i2) = 0

Factor a trinomial.
2((1 + -1i)(4 + -1i)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(1 + -1i)' equal to zero and attempt to solve: Simplifying 1 + -1i = 0 Solving 1 + -1i = 0 Move all terms containing i to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1i = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1i = 0 + -1 -1i = 0 + -1 Combine like terms: 0 + -1 = -1 -1i = -1 Divide each side by '-1'. i = 1 Simplifying i = 1

Subproblem 2

Set the factor '(4 + -1i)' equal to zero and attempt to solve: Simplifying 4 + -1i = 0 Solving 4 + -1i = 0 Move all terms containing i to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1i = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1i = 0 + -4 -1i = 0 + -4 Combine like terms: 0 + -4 = -4 -1i = -4 Divide each side by '-1'. i = 4 Simplifying i = 4

Solution

i = {1, 4}

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