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(8+2x)(26+2x)=544
We move all terms to the left:
(8+2x)(26+2x)-(544)=0
We add all the numbers together, and all the variables
(2x+8)(2x+26)-544=0
We multiply parentheses ..
(+4x^2+52x+16x+208)-544=0
We get rid of parentheses
4x^2+52x+16x+208-544=0
We add all the numbers together, and all the variables
4x^2+68x-336=0
a = 4; b = 68; c = -336;
Δ = b2-4ac
Δ = 682-4·4·(-336)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-100}{2*4}=\frac{-168}{8} =-21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+100}{2*4}=\frac{32}{8} =4 $
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