(8)/(3)c-2=(2)/(3)c-12

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Solution for (8)/(3)c-2=(2)/(3)c-12 equation: 



(8)/(3)c-2=(2)/(3)c-12

We move all terms to the left:

(8)/(3)c-2-((2)/(3)c-12)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R





Domain of the equation: 3c-12)!=0

c∈R



We get rid of parentheses

8/3c-2/3c+12-2=0

We multiply all the terms by the denominator


12*3c-2*3c+8-2=0

We add all the numbers together, and all the variables

12*3c-2*3c+6=0

Wy multiply elements

36c-6c+6=0

We add all the numbers together, and all the variables

30c+6=0

We move all terms containing c to the left, all other terms to the right

30c=-6

c=-6/30

c=-1/5

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