(8(x-3))/(-3x+1)(-x+2)=0

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Solution for (8(x-3))/(-3x+1)(-x+2)=0 equation: 


D( x )

1-3*x = 0

1-3*x = 0

1-3*x = 0

1-3*x = 0 // - 1

-3*x = -1 // : -3

x = -1/(-3)

x = 1/3

x in (-oo:1/3) U (1/3:+oo)

((8*(x-3))/(1-3*x))*(2-x) = 0

(8*(x-3)*(2-x))/(1-3*x) = 0

( 2-x )

2-x = 0 // - 2

-x = -2 // * -1

x = 2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { 2, 3 }

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