(7z-3y)-(4z-5y)=2y+3z

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Solution for (7z-3y)-(4z-5y)=2y+3z equation:


Simplifying
(7z + -3y) + -1(4z + -5y) = 2y + 3z

Reorder the terms:
(-3y + 7z) + -1(4z + -5y) = 2y + 3z

Remove parenthesis around (-3y + 7z)
-3y + 7z + -1(4z + -5y) = 2y + 3z

Reorder the terms:
-3y + 7z + -1(-5y + 4z) = 2y + 3z
-3y + 7z + (-5y * -1 + 4z * -1) = 2y + 3z
-3y + 7z + (5y + -4z) = 2y + 3z

Reorder the terms:
-3y + 5y + 7z + -4z = 2y + 3z

Combine like terms: -3y + 5y = 2y
2y + 7z + -4z = 2y + 3z

Combine like terms: 7z + -4z = 3z
2y + 3z = 2y + 3z

Add '-2y' to each side of the equation.
2y + -2y + 3z = 2y + -2y + 3z

Combine like terms: 2y + -2y = 0
0 + 3z = 2y + -2y + 3z
3z = 2y + -2y + 3z

Combine like terms: 2y + -2y = 0
3z = 0 + 3z
3z = 3z

Add '-3z' to each side of the equation.
3z + -3z = 3z + -3z

Combine like terms: 3z + -3z = 0
0 = 3z + -3z

Combine like terms: 3z + -3z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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