(7y/3y+9)+(4y-18/2y+6)=(3y-13/y+3)

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Solution for (7y/3y+9)+(4y-18/2y+6)=(3y-13/y+3) equation: 



(7y/3y+9)+(4y-18/2y+6)=(3y-13/y+3)

We move all terms to the left:

(7y/3y+9)+(4y-18/2y+6)-((3y-13/y+3))=0



Domain of the equation: 3y+9)!=0

y∈R





Domain of the equation: 2y+6)!=0

y∈R





Domain of the equation: y+3))!=0

y∈R



We get rid of parentheses

7y/3y+4y-18/2y-((3y-13/y+3))+9+6=0

We calculate fractions

We do not support eypression: y^3

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