(7y/10)=(5/6)

Solution for (7y/10)=(5/6) equation:

(7y/10)=(5/6)

We move all terms to the left:

(7y/10)-((5/6))=0

We add all the numbers together, and all the variables

(+7y/10)-((+5/6))=0

We get rid of parentheses

7y/10-((+5/6))=0

We calculate fractions


42y^2/()+()/()=0

We add all the numbers together, and all the variables

42y^2/()+1=0

We multiply all the terms by the denominator


42y^2+1*()=0

We add all the numbers together, and all the variables

42y^2=0

a = 42; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·42·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{84}=0$