(7y-4)+(y-5)=28

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Solution for (7y-4)+(y-5)=28 equation: 



(7y-4)+(y-5)=28

We move all terms to the left:

(7y-4)+(y-5)-(28)=0

We get rid of parentheses

7y+y-4-5-28=0

We add all the numbers together, and all the variables

8y-37=0

We move all terms containing y to the left, all other terms to the right

8y=37

y=37/8

y=4+5/8

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