(7y+3)=(4y+15)

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Solution for (7y+3)=(4y+15) equation: 



(7y+3)=(4y+15)

We move all terms to the left:

(7y+3)-((4y+15))=0

We get rid of parentheses

7y-((4y+15))+3=0



We calculate terms in parentheses: -((4y+15)), so:

(4y+15)

We get rid of parentheses

4y+15

Back to the equation:

-(4y+15)



We get rid of parentheses

7y-4y-15+3=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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