(7y+3)+(3y+4)=12y-3

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Solution for (7y+3)+(3y+4)=12y-3 equation: 



(7y+3)+(3y+4)=12y-3

We move all terms to the left:

(7y+3)+(3y+4)-(12y-3)=0

We get rid of parentheses

7y+3y-12y+3+4+3=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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