(7y+2)/5=(6y-5)/11

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Solution for (7y+2)/5=(6y-5)/11 equation: 



(7y+2)/5=(6y-5)/11

We move all terms to the left:

(7y+2)/5-((6y-5)/11)=0

We calculate fractions


7y/()+(-((6y-5)*5)/()=0



We calculate terms in parentheses: +(-((6y-5)*5)/(), so:

-((6y-5)*5)/(

We multiply all the terms by the denominator


-((6y-5)*5)



We calculate terms in parentheses: -((6y-5)*5), so:

(6y-5)*5

We multiply parentheses

30y-25

Back to the equation:

-(30y-25)



We get rid of parentheses

-30y+25

Back to the equation:

+(-30y+25)



We get rid of parentheses

7y/()-30y+25=0

We multiply all the terms by the denominator


7y-30y*()+25*()=0

We add all the numbers together, and all the variables

7y-30y*()=0

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