(7y^2+3xy-9)-(2y^2+3xy-5)=

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Solution for (7y^2+3xy-9)-(2y^2+3xy-5)= equation:


Simplifying
(7y2 + 3xy + -9) + -1(2y2 + 3xy + -5) = 0

Reorder the terms:
(-9 + 3xy + 7y2) + -1(2y2 + 3xy + -5) = 0

Remove parenthesis around (-9 + 3xy + 7y2)
-9 + 3xy + 7y2 + -1(2y2 + 3xy + -5) = 0

Reorder the terms:
-9 + 3xy + 7y2 + -1(-5 + 3xy + 2y2) = 0
-9 + 3xy + 7y2 + (-5 * -1 + 3xy * -1 + 2y2 * -1) = 0
-9 + 3xy + 7y2 + (5 + -3xy + -2y2) = 0

Reorder the terms:
-9 + 5 + 3xy + -3xy + 7y2 + -2y2 = 0

Combine like terms: -9 + 5 = -4
-4 + 3xy + -3xy + 7y2 + -2y2 = 0

Combine like terms: 3xy + -3xy = 0
-4 + 0 + 7y2 + -2y2 = 0
-4 + 7y2 + -2y2 = 0

Combine like terms: 7y2 + -2y2 = 5y2
-4 + 5y2 = 0

Solving
-4 + 5y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5y2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 5y2 = 0 + 4
5y2 = 0 + 4

Combine like terms: 0 + 4 = 4
5y2 = 4

Divide each side by '5'.
y2 = 0.8

Simplifying
y2 = 0.8

Take the square root of each side:
y = {-0.894427191, 0.894427191}

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