(7x/9)+(x/2)-(17/9)=(2/3)

Solution for (7x/9)+(x/2)-(17/9)=(2/3) equation:

(7x/9)+(x/2)-(17/9)=(2/3)

We move all terms to the left:

(7x/9)+(x/2)-(17/9)-((2/3))=0

We add all the numbers together, and all the variables

(+7x/9)+(+x/2)-(+17/9)-((+2/3))=0

We get rid of parentheses

7x/9+x/2-17/9-((+2/3))=0

We calculate fractions


81x^2/()+7x/()+()/()=0

We add all the numbers together, and all the variables

81x^2/()+7x/()+1=0

We multiply all the terms by the denominator


81x^2+7x+1*()=0

We add all the numbers together, and all the variables

81x^2+7x=0

a = 81; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·81·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*81}=\frac{-14}{162}
=-7/81
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*81}=\frac{0}{162}
=0
$