(7x-8/1-4x)=(x-20/x+8)

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Solution for (7x-8/1-4x)=(x-20/x+8) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7*x-(4*x)-(8/1) = x-(20/x)+8 // - x-(20/x)+8

7*x-(4*x)-x+20/x-(8/1)-8 = 0

7*x-4*x-x+20/x-8-8 = 0

2*x^1+20*x^-1-16*x^0 = 0

(2*x^2-16*x^1+20*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-16*x^1+20*x^0) = 0

x^1

2*x^2-16*x+20 = 0

2*x^2-16*x+20 = 0

DELTA = (-16)^2-(2*4*20)

DELTA = 96

DELTA > 0

x = (96^(1/2)+16)/(2*2) or x = (16-96^(1/2))/(2*2)

x = (4*6^(1/2)+16)/4 or x = (16-4*6^(1/2))/4

x in { (16-4*6^(1/2))/4, (4*6^(1/2)+16)/4} 

x in { (16-4*6^(1/2))/4, (4*6^(1/2)+16)/4 }

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