(7x-8)=(2x+7)+65

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Solution for (7x-8)=(2x+7)+65 equation: 



(7x-8)=(2x+7)+65

We move all terms to the left:

(7x-8)-((2x+7)+65)=0

We get rid of parentheses

7x-((2x+7)+65)-8=0



We calculate terms in parentheses: -((2x+7)+65), so:

(2x+7)+65

We get rid of parentheses

2x+7+65

We add all the numbers together, and all the variables

2x+72

Back to the equation:

-(2x+72)



We get rid of parentheses

7x-2x-72-8=0

We add all the numbers together, and all the variables

5x-80=0

We move all terms containing x to the left, all other terms to the right

5x=80

x=80/5

x=16

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