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(7x-8)(x+3)=7x
We move all terms to the left:
(7x-8)(x+3)-(7x)=0
We add all the numbers together, and all the variables
-7x+(7x-8)(x+3)=0
We multiply parentheses ..
(+7x^2+21x-8x-24)-7x=0
We get rid of parentheses
7x^2+21x-8x-7x-24=0
We add all the numbers together, and all the variables
7x^2+6x-24=0
a = 7; b = 6; c = -24;
Δ = b2-4ac
Δ = 62-4·7·(-24)
Δ = 708
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{708}=\sqrt{4*177}=\sqrt{4}*\sqrt{177}=2\sqrt{177}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{177}}{2*7}=\frac{-6-2\sqrt{177}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{177}}{2*7}=\frac{-6+2\sqrt{177}}{14} $
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