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(7x-6)(6x+9)=0
We multiply parentheses ..
(+42x^2+63x-36x-54)=0
We get rid of parentheses
42x^2+63x-36x-54=0
We add all the numbers together, and all the variables
42x^2+27x-54=0
a = 42; b = 27; c = -54;
Δ = b2-4ac
Δ = 272-4·42·(-54)
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9801}=99$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-99}{2*42}=\frac{-126}{84} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+99}{2*42}=\frac{72}{84} =6/7 $
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