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(7x-6)(4x-1)=0
We multiply parentheses ..
(+28x^2-7x-24x+6)=0
We get rid of parentheses
28x^2-7x-24x+6=0
We add all the numbers together, and all the variables
28x^2-31x+6=0
a = 28; b = -31; c = +6;
Δ = b2-4ac
Δ = -312-4·28·6
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-17}{2*28}=\frac{14}{56} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+17}{2*28}=\frac{48}{56} =6/7 $
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