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(7x-6)(10x+7)=0
We multiply parentheses ..
(+70x^2+49x-60x-42)=0
We get rid of parentheses
70x^2+49x-60x-42=0
We add all the numbers together, and all the variables
70x^2-11x-42=0
a = 70; b = -11; c = -42;
Δ = b2-4ac
Δ = -112-4·70·(-42)
Δ = 11881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11881}=109$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-109}{2*70}=\frac{-98}{140} =-7/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+109}{2*70}=\frac{120}{140} =6/7 $
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