(7x-5)=(5x+27)

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Solution for (7x-5)=(5x+27) equation: 



(7x-5)=(5x+27)

We move all terms to the left:

(7x-5)-((5x+27))=0

We get rid of parentheses

7x-((5x+27))-5=0



We calculate terms in parentheses: -((5x+27)), so:

(5x+27)

We get rid of parentheses

5x+27

Back to the equation:

-(5x+27)



We get rid of parentheses

7x-5x-27-5=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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