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(7x-5)(x+9)=0
We multiply parentheses ..
(+7x^2+63x-5x-45)=0
We get rid of parentheses
7x^2+63x-5x-45=0
We add all the numbers together, and all the variables
7x^2+58x-45=0
a = 7; b = 58; c = -45;
Δ = b2-4ac
Δ = 582-4·7·(-45)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-68}{2*7}=\frac{-126}{14} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+68}{2*7}=\frac{10}{14} =5/7 $
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