(7x-4)=(4x+53)

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Solution for (7x-4)=(4x+53) equation: 



(7x-4)=(4x+53)

We move all terms to the left:

(7x-4)-((4x+53))=0

We get rid of parentheses

7x-((4x+53))-4=0



We calculate terms in parentheses: -((4x+53)), so:

(4x+53)

We get rid of parentheses

4x+53

Back to the equation:

-(4x+53)



We get rid of parentheses

7x-4x-53-4=0

We add all the numbers together, and all the variables

3x-57=0

We move all terms containing x to the left, all other terms to the right

3x=57

x=57/3

x=19

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