(7x-4)-(4x+2)=(x-5)-(6x+14)

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Solution for (7x-4)-(4x+2)=(x-5)-(6x+14) equation: 



(7x-4)-(4x+2)=(x-5)-(6x+14)

We move all terms to the left:

(7x-4)-(4x+2)-((x-5)-(6x+14))=0

We get rid of parentheses

7x-4x-((x-5)-(6x+14))-4-2=0



We calculate terms in parentheses: -((x-5)-(6x+14)), so:

(x-5)-(6x+14)

We get rid of parentheses

x-6x-5-14

We add all the numbers together, and all the variables

-5x-19

Back to the equation:

-(-5x-19)



We add all the numbers together, and all the variables

3x-(-5x-19)-6=0

We get rid of parentheses

3x+5x+19-6=0

We add all the numbers together, and all the variables

8x+13=0

We move all terms containing x to the left, all other terms to the right

8x=-13

x=-13/8

x=-1+5/8

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