(7x-4)+19(10x+13)=52

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Solution for (7x-4)+19(10x+13)=52 equation: 



(7x-4)+19(10x+13)=52

We move all terms to the left:

(7x-4)+19(10x+13)-(52)=0

We multiply parentheses

(7x-4)+190x+247-52=0

We get rid of parentheses

7x+190x-4+247-52=0

We add all the numbers together, and all the variables

197x+191=0

We move all terms containing x to the left, all other terms to the right

197x=-191

x=-191/197

x=-191/197

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