(7x-3)/2+(4x-5)/6=-19

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Solution for (7x-3)/2+(4x-5)/6=-19 equation: 



(7x-3)/2+(4x-5)/6=-19

We move all terms to the left:

(7x-3)/2+(4x-5)/6-(-19)=0

We add all the numbers together, and all the variables

(7x-3)/2+(4x-5)/6+19=0

We calculate fractions

There is no solution for this equation

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