(7x-3)+2(x+3)=18-5(x+1)-2x

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Solution for (7x-3)+2(x+3)=18-5(x+1)-2x equation: 



(7x-3)+2(x+3)=18-5(x+1)-2x

We move all terms to the left:

(7x-3)+2(x+3)-(18-5(x+1)-2x)=0

We multiply parentheses

(7x-3)+2x-(18-5(x+1)-2x)+6=0

We get rid of parentheses

7x+2x-(18-5(x+1)-2x)-3+6=0



We calculate terms in parentheses: -(18-5(x+1)-2x), so:

18-5(x+1)-2x

determiningTheFunctionDomain
-5(x+1)-2x+18

We add all the numbers together, and all the variables

-2x-5(x+1)+18

We multiply parentheses

-2x-5x-5+18

We add all the numbers together, and all the variables

-7x+13

Back to the equation:

-(-7x+13)



We add all the numbers together, and all the variables

9x-(-7x+13)+3=0

We get rid of parentheses

9x+7x-13+3=0

We add all the numbers together, and all the variables

16x-10=0

We move all terms containing x to the left, all other terms to the right

16x=10

x=10/16

x=5/8

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