(7x-3)+(3x)=4x+27

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Solution for (7x-3)+(3x)=4x+27 equation: 



(7x-3)+(3x)=4x+27

We move all terms to the left:

(7x-3)+(3x)-(4x+27)=0

We add all the numbers together, and all the variables

3x+(7x-3)-(4x+27)=0

We get rid of parentheses

3x+7x-4x-3-27=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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