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(7x-3)(6x+17)=180
We move all terms to the left:
(7x-3)(6x+17)-(180)=0
We multiply parentheses ..
(+42x^2+119x-18x-51)-180=0
We get rid of parentheses
42x^2+119x-18x-51-180=0
We add all the numbers together, and all the variables
42x^2+101x-231=0
a = 42; b = 101; c = -231;
Δ = b2-4ac
Δ = 1012-4·42·(-231)
Δ = 49009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(101)-\sqrt{49009}}{2*42}=\frac{-101-\sqrt{49009}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(101)+\sqrt{49009}}{2*42}=\frac{-101+\sqrt{49009}}{84} $
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