(7x-26)+(5x-27)=(10x-23)

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Solution for (7x-26)+(5x-27)=(10x-23) equation: 



(7x-26)+(5x-27)=(10x-23)

We move all terms to the left:

(7x-26)+(5x-27)-((10x-23))=0

We get rid of parentheses

7x+5x-((10x-23))-26-27=0



We calculate terms in parentheses: -((10x-23)), so:

(10x-23)

We get rid of parentheses

10x-23

Back to the equation:

-(10x-23)



We add all the numbers together, and all the variables

12x-(10x-23)-53=0

We get rid of parentheses

12x-10x+23-53=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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