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(7x-26)(4x+43)=180
We move all terms to the left:
(7x-26)(4x+43)-(180)=0
We multiply parentheses ..
(+28x^2+301x-104x-1118)-180=0
We get rid of parentheses
28x^2+301x-104x-1118-180=0
We add all the numbers together, and all the variables
28x^2+197x-1298=0
a = 28; b = 197; c = -1298;
Δ = b2-4ac
Δ = 1972-4·28·(-1298)
Δ = 184185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184185}=\sqrt{9*20465}=\sqrt{9}*\sqrt{20465}=3\sqrt{20465}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(197)-3\sqrt{20465}}{2*28}=\frac{-197-3\sqrt{20465}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(197)+3\sqrt{20465}}{2*28}=\frac{-197+3\sqrt{20465}}{56} $
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