(7x-23)+(6x-19)=(10x-9)

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Solution for (7x-23)+(6x-19)=(10x-9) equation: 



(7x-23)+(6x-19)=(10x-9)

We move all terms to the left:

(7x-23)+(6x-19)-((10x-9))=0

We get rid of parentheses

7x+6x-((10x-9))-23-19=0



We calculate terms in parentheses: -((10x-9)), so:

(10x-9)

We get rid of parentheses

10x-9

Back to the equation:

-(10x-9)



We add all the numbers together, and all the variables

13x-(10x-9)-42=0

We get rid of parentheses

13x-10x+9-42=0

We add all the numbers together, and all the variables

3x-33=0

We move all terms containing x to the left, all other terms to the right

3x=33

x=33/3

x=11

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